regEx syntax for removal of first or last field in a string

[Fellow Starmadian]

BIG EDIT: This is no longer a question, but an answer.
SECOND BIG EDIT: This is no longer a question, but an archived post. This thread has a more updated solution: RegEx compilation thread

The question:
So something has been bugging me for quite a while now, something that would totally revolutionize the starmade world. I've actually discussed this with a couple other users for a while now, and we can't find a solution so I'm forced to ask here.

Is there any way to have a display read one word at a time, with multiple words on a single line? Something like this:

[display 1] "the quick red fox jumps over the lazy brown dog"
[display 2]REPLACEALL words 2 through 99 with " "

and feed that statement through the first display block to be left with the word: "the "

This is what I have so far, but it doesnt work. Might illustrate better what I wanted though:
Regex101 - online regex editor and debugger

The answer: Pt.1

so I think I finally managed to get this to do half of what I want now, use this code to remove the first field from the string:

[replaceall]^(?:[^:]*\:BACK PARENTHESES{1}([^:]*:BACK PARENTHESES [with]:

(replace the capital words with one of these ")"

the string has to start with a : Each field has to end with a : for the next field to start.
EX: <:the super: A E S T H E T I C : ship: build:>

then we just need one to remove the last field.

edit: this is only half of what I need it to do, not all.

so this removes the first occurence (or any number of occurences with the number in { }:
[replaceall]^(?:[^:]*\:BACK PARENTHESES{1}([^:]*:BACK PARENTHESES [with]:

The answer: Pt.2

ok so here's the other part to this, it all had to do with this symbol "$" which forces regex to look at the end of the line, or something :/ anywho, here's the code:
[replaceall]([^:]*:BACK PARENTHESES$[with]x

Now I need a way to duplicate what the other part of the code does, which is replace the last field without having to use another display block with [del]1 so I can get rid of the X.

update 1: use this code to delete any number of fields from the end that you like, just like the one that removes from the front: [replaceall]([^:]*BACK PARENTHESES{1}$[with]:

still have to use [del]1 though afterwards..

And this one removes the last occurrence:
[replaceall]([^:]*:BACK PARENTHESES{1}$[with]:

So My new question is this: How do you guys think this can be used? Here's a hasty and vague gif of how I intend to use it:

Spoiler

 

[nightrune]

I think there are a number of ways to approach this. What is the end result you want? and what is the actual input?

 

[Jaaskinal]

I don't believe there's a fast way of doing this, but with instant pulses, regex, and DEL, you can do a lot of weird shit

 

[Fellow Starmadian]

well I want a way, in however many stages is required, to send each word to a different display block. obv. it has to be configured beforehand to a maximum number of words, I just don't know the regexp necessary to do it. So I guess I need a way to delete everything before the last word?

 

[Jaaskinal]

Thing is, it's really easy to parse backwards, i.e. remove one word at a time, compared to parsing forwards, adding one word at a time.
I might try to do something with this tho.

 

[Fellow Starmadian]

so I think I finally managed to get this to do half of what I want now, use this code to remove the first field from the string:

[replaceall]^(?:[^:]*\:BACK PARENTHESES{1}([^:]*:BACK PARENTHESES [with]:

(replace the capital words with one of these ")"

the string has to start with a : Each field has to end with a : for the next field to start.
EX: <:the super: A E S T H E T I C : ship: build:>

then we just need one to remove the last field.

edit: this is only half of what I need it to do, not all.

 

[Fellow Starmadian]

ok so here's the other part to this, it all had to do with this symbol "$" which forces regex to look at the end of the line, or something :/ anywho, here's the code:
[replaceall]([^:]*:BACK PARENTHESES$[with]x

Now I need a way to duplicate what the other part of the code does, which is replace the last field without having to use another display block with [del]1 so I can get rid of the X.

update 1: use this code to delete any number of fields from the end that you like, just like the one that removes from the front: [replaceall]([^:]*BACK PARENTHESES{1}$[with]:

still have to use [del]1 though afterwards..
[doublepost=1485207738,1485207095][/doublepost]

Thing is, it's really easy to parse backwards, i.e. remove one word at a time, compared to parsing forwards, adding one word at a time.
I might try to do something with this tho.

What do you mean by saying "add one word at a time."? adding words is easy, just use [add] :P

 

[GalactusX]

What do you want to do, take a string of characters, and separate each "word/match" into a different display?
for example:
display 1 ":the super: A E S T H E T I C : ship: build:"
display 2 ":the super:" ...
display 3 ": A E S T H E T I C :" ...
display 4 ":ship:" ...
display 5 ":build:"

is this correct?

 

[GalactusX]

This is what you want to do?

​

This do 2 things, convert the first group in to a "non-group match" (This excludes the text of the captured group) and then select the rest of the string
[REPLACEALL](?:(:\w+:))(.?)*[WITH]$1

Regex101 - online regex editor and debugger

This other regex, select the first group match and replace with a empty refference using $3
[REPLACEALL]^(:([^:]*:\s){1})()[WITH]$3

Regex101 - online regex editor and debugger