Well, I imagine you could still use it to reduce the number of blocks. I haven't tested it but I assume it should work to use the flip flops to get to the nearest power of two <= your target value and then chain a few delay blocks after that to hit the desired value.
Would you mind clarifying your instructions for odd numbers? If I wanted 7, what exactly would be the setup? If I follow the instructions exactly. Halving 7 = 3.5(non integer) = D and you divided once = F. 3.5 delay blocks and 1 flip flop?
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.